If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2x^2+10x-26=0
a = 2; b = 10; c = -26;
Δ = b2-4ac
Δ = 102-4·2·(-26)
Δ = 308
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{308}=\sqrt{4*77}=\sqrt{4}*\sqrt{77}=2\sqrt{77}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2\sqrt{77}}{2*2}=\frac{-10-2\sqrt{77}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2\sqrt{77}}{2*2}=\frac{-10+2\sqrt{77}}{4} $
| 6^x=13^(5-x) | | 2x−14=6 | | 21x-5=16^7x-2.5 | | 2n+4n+2=38 | | 0.3*b=0.9. | | x²+x²=25 | | (12y-19)+(6y+1)=90 | | 2(w-9)=-8 | | 3(p+3)=2(2-p) | | -(x+3)+(x-9+x=-10 | | 6^x=13^5-x | | 1)y=620 | | 0.2(x+1)=5x+7.4 | | 18v-17v=17 | | 8/72=16/x | | (k+4)(5k-1)=0 | | -1(x+3)+1(x-9)+x=-10 | | -4n+10=-n+16 | | (11y-36)+63-180=117 | | -18.5=-9.5(4.5n+5.5) | | n+(n-1)+(n-2)+(n-3)+(n-4)+…+1=100 | | 10x4x=35+x | | -6k-5.5+9.5k=—25.5 | | 15=-2+4-d | | 14n+20=9n+50 | | 15+4y=63 | | 16-6+10x=50 | | 6-2(-3x+4)+x=26 | | (x+5)/4=-3 | | 17=t-(-9) | | 66=πr^2(3.3) | | (2x-37)+(90)=3x |